Answer:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Step-by-step explanation:
For this case we define W as the random variable who represent the number of heads minus the number of tails in three tosses of a coin.
W= # heads- # coins
Since we toss a coin 3 times we have 2*2*2= 8 possible results. We can list the results and the corresponding values for W like this:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Answer:
A
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
−y+4≥8
Step 2: Subtract 4 from both sides.
−y+4−4≥8−4
−y≥4
Step 3: Divide both sides by -1.
−y
−1
≥
4
−1
y≤−4
The answer is it is yes, it is sometimes true, y can =0
Explanation
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