Answer:
yessss I tooo have a fire at my home
lolololololololololo
ok have a great day what is your name ?
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
f(x) = x² + 1, x > 0
y = x² + 1
x = y² + 1
x - 1 = y²
√x - 1 = y
√x - 1 = f(x), x > 1
The print_shape() is an illustration of Python function; whose execution is carried out when the function is called
<h3>The print_shape() function</h3>
The print_shape() function written in Python, where comments are used to explain each action is as follows:
#This defines the function
def print_shape():
#The following iteration is repeated three times
for i in range(3):
#This prints the *** in each iteration
print('***')
#This calls the function
print_shape()
Read more about Python functions at:
brainly.com/question/15745784
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I rearranged them so the program would make sense by arranging the interaction in a logical order then placing input statements in between
