All categories

2 years ago

If 3 cans of beans cost 90¢, how many can you buy for $2.70?

Mathematics

2 answers:

olga55 [171]2 years ago

8 0

Answer:

Step-by-step explanation:

1. 3 cans cost 90 cents

3=0.90 & x=2.7

by ratio:

3/0.9 = x/2.7

0.9x=8.1

x= 9

So you can buy 9 cans for 2.7 dollars

2. 10 Juice cost 3 dollars

by ratio:

10/3 = 4/x

10x=12

x=1.2

so you will spend 1.2 dollars to buy 4 juice packs

Slav-nsk [51]2 years ago

3 0

9 cans of beans and spend around 13.25 dollars

You might be interested in

Please help, the questions just have to be simplified

dimaraw [331]

$6c^2d^{-3}\ \times\ 3c^3d^{-4}=6\cdot3\cdot c^{2+3}d^{-3+(-4)}=18c^5d^{-7}=\frac{18c^5}{d^7}$

$\frac{-16p^6q^5}{20q^7}=-\frac{16}{20}p^6q^{5-7}=-\frac{4}{5}p^6q^{-2}=-\frac{4p^5}{5q^2}$

8 0

3 years ago

Read 2 more answers

Alex and bob are playing 5 chess games. Alex is 3 times more likely to win than bob. What is the probability that both of them w

givi [52]

Answer:

12.2%

Step-by-step explanation:

Lets firstly find out the probabilities for Alex and Bob. We know that the prb that Alex wins is 3 times the prob for Bob, so:

P(A) = 3P(B)

And, as these values are probabilities they must sum 1:

P(A) + P(B) = 1

Replacing the first equation in the second:

3P(B) + P(B) = 1

4P(B) = 1

Dividing both sided by 4:

4P(B)/4 = 1/4

P(B) =1/4

So, the probability for Bob is 1/4. Then the probability for Alex is 3*1/4 = 3/4

Now we have to find the probability that both win at least two games. Lets think about the possible combination of cases. As they play 5 games and both have to win at least to there is a remaining game that cane variate, this is, can be won by Alex or Bob. So, we can have:

AABBB

AABBA

Where A is "Alex win" and B is "Bob win" (here we do not pay attention to the order).

Thus, we have to find the probability that Alex wins 3 games and Bob 2 games, and the probability that Alex wins 2 games and Bob 3 games. As the games are independent, i.e., the result of one games does not affect the followings we can just multiply the probabilities:

P(3A and 2B) = (3/4)*(3/4)*(3/4)*(1/4)*(1/4) = 0.42*0.06 = 0.026

P(2A and 3B) = (3/4)*(3/4)*(1/4)*(1/4)*(1/4) = 0.56*0.016 = 0.096

So,

P (at least 2) = P(3A and 2B) + P(2A and 3B) = 0.026 + 0.096 = 0.122 = 12.2%

7 0

3 years ago

A line has a slope of -2/3 and passes through the point (-3,8). What is the equation of the line?

LiRa [457]

Answer:

Step-by-step explanation:

We'll use the standard equation y=mx+b to solve this problem. m is the slope of the line and b is the y intercept.

We know the slope, but we have to solve for the y intercept. To do this (I mean solve for 'b'), we need to know the slope, x value, and y value. We know the slope (-2/3), x= -3, and y=8. Let's plug this into y=mx+b and solve for b.

$y=mx+b\\8=-\frac{2}{3}*-3 +b\\8=2+b\\b=8-2\\b=6$