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TEA [102]
3 years ago
5

What are the zeros for the function f(x)=x^3-4x

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

x = 0

x = 2

x = -2

Step-by-step explanation:

f(x) = x^{3} - 4x

Factor

f(x) = x ( x^{2} - 4)

f(x) = x ( ( x - 2 ) ( x + 2 ) )

zeros;

x = 0

x = 2

x = -2

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Answer:

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Step-by-step explanation:

We need to solve the linear system of equations.

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We can write second equation y=x-4  as: -x+y=-4

Let:

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Now, Adding equation 1 and 2

3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1

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So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

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