What are the zeros for the function f(x)=x^3-4x

Mathematics

1 answer:

Harman [31]3 years ago

4 0

Answer:

x = 0

x = 2

x = -2

Step-by-step explanation:

f(x) = $x^{3}$ - 4x

Factor

f(x) = x ( $x^{2}$ - 4)

f(x) = x ( ( x - 2 ) ( x + 2 ) )

zeros;

x = 0

x = 2

x = -2

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