Answer:
The outer diameter of the shaft to 2s.f is 12.65cm
Step-by-step explanation:
We know that the expression for the area of a circular cross section is
A= 
given data
area of cross section= 
bore diameter d= 8cm
from the area of cross section we can solve for the outer diameter D
solving for D we have
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis :
H0 : μ = 3000
H0 : μ ≠ 3000
The test statistic :
(xbar - μ) ÷ (s/√(n))
xbar = 3500
μ = 3000
σ = 300
n = 30
(3500 - 3000) ÷ (350/√(30))
Test statistic = 7.824
Df = 30 - 1 = 29
Tcritical at 0.01 = 2.462
Test statistic > critical value ; we reject H0 ; and concluded that there is significant evidence that
μ ≠ 3000
Answer:
Step-by-step explanation:
Slope (m) =
ΔY
ΔX
= 0
θ =
arctan( ΔY )
ΔX
= 0°
ΔX = 6 – 2 = 4
ΔY = -3 – -3 = 0
Distance (d) = √ΔX2 + ΔY2 = √16 = 4
Equation of the line:
y = 0x – 3
When x=0, y = -3
Answer:
156 barrels, 26 minutes
Step-by-step explanation:
The amount of minutes since the worker has started to work: x
Convertor: 26+5x
Worker: 6x
Since the question stated that the number of completed barrels are the same: 26+5x=6x
x=26
It has been 26 minutes and each line has 156 barrels filled out.
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Answer:
8 units
Step-by-step explanation:
The longer leg extends upward from y = -3 to y = 5, so its length is 8 units.
