∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
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Answer:
how much does 1 pound cost?
Answer:
4/72-5/8#3
Step-by-step explanation:
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Add the numbers: 3+17 = 20
-x + 5 < -1/20
Apply the fraction rule: -a/b = - a/b
-x + 5 < - 1/20
Subtract 5 from both sides
-x + 5 - 5 < 1/20 - 5
Simplify
-x< - 101/20
Multiply both sides by -1 (reverse the inequality)
(-x) (-1) > (-101/20) (-1)
x> 101/20 is the final answer