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katrin2010 [14]
3 years ago
7

How to factor a tri, quad, or polynomial.

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Explanation:

Factoring to linear factors generally involves finding the roots of the polynomial.

The two rules that are taught in Algebra courses for finding real roots of polynomials are ...

  • Descartes' rule of signs: the number of positive real roots is equal to the number of coefficient sign changes when the polynomial is written in standard form.
  • Rational root theorem: possible rational roots will have a numerator magnitude that is a divisor of the constant, and a denominator magnitude that is a divisor of the leading coefficient when the coefficients of the polynomial are rational. (Trial and error will narrow the selection.)

In general, it is a difficult problem to find irrational real factors, and even more difficult to find complex factors. The methods for finding complex factors are not generally taught in beginning Algebra courses, but may be taught in some numerical analysis courses.

Formulas exist for finding the roots of quadratic, cubic, and quartic polynomials. Above 2nd degree, they tend to be difficult to use, and may produce results that are less than easy to use. (The real roots of a cubic may be expressed in terms of cube roots of a complex number, for example.)

__

Personally, I find a graphing calculator to be exceptionally useful for finding real roots. A suitable calculator can find irrational roots to calculator precision, and can use that capability to find a pair of complex roots if there is only one such pair.

There are web apps that will find all roots of virtually any polynomial of interest.

_____

<em>Additional comment</em>

Some algebra courses teach iterative methods for finding real zeros. These can include secant methods, bisection, and Newton's method iteration. There are anomalous cases that make use of these methods somewhat difficult, but they generally can work well if an approximate root value can be found.

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Sally makes $9.15 per hour. If she works 3.5 hours, how much money will she make?
liraira [26]

Answer:

$12.65

Step-by-step explanation:

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5 0
3 years ago
Lucas and his brother, Max, went to the arcade yesterday. Lucas played 2 games of Rodeo Racing and 8 games of Polar Pinball. Max
Umnica [9.8K]

Answer:

Max

Step-by-step explanation:

Lucas played 2 Rodeo Racing:8 Polar pinball = 1:4 (Divide by 2)

Max played 3 Rodeo Racing:9 Polar pinball = 1:3 (Divide by 3)

1:3 is greater than 1:4 so this proves that Max has played the greater ration of Rodeo Racing to Polar Pinball.

8 0
3 years ago
b. A 2017 poll found that 55​% of college students were very confident that their major will lead to a good job. If 25 college s
Sergeu [11.5K]

Answer:0.124

Step-by-step explanation:

Using binomial distribution,

p =1-0.55=0.45

q = 0.55

n = 25

P( x=13) = 25 combination 13 x 0.55^12×0.45^ 13

= 0.124

8 0
4 years ago
Given P(A)=0.34P(A)=0.34, P(B)=0.45P(B)=0.45 and P(A\text{ or }B)=0.517P(A or B)=0.517, find the value of P(A\text{ and }B)P(A a
maria [59]
Easy this answer is going to be 0.517 you can read and round
8 0
3 years ago
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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