Calculate the hypotenuse( h ) using Pythagoras' identity
h =√(4² + 7²) = √(16 + 49) = √65
sinΘ = 4 / √65 ⇒ cscθ = √65 / 4
cosθ = 7/ √65 ⇒ secθ = √65 / 7
tanθ =
⇒ cotθ = ![\frac{7}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B4%7D)
(10x+5) + (6x-1)=180
10x+5+6x-1=180
16x+4=180
16x+4=180
16x=180-4
16x=178
x=11
Answer:
The value of x = 9
Step-by-step explanation:
∵ The figure has right angle and a line ⊥ from the right angle to the hypotenuse
∴ There is a relation between the ⊥ line and the two parts of the hypotenuse
∴ (⊥)² = multiplication of the two parts of the hypotenuse
∴ (6)²= 4 × x
∴ 36 = 4 × x
∴ x = 36/4 = 9
Parallel because the Y moved 4 units down and the slope hasnt changed