Answer:
-39
Step-by-step explanation:
![\left(-3\right)^3-\sqrt[3]{27}-4^3\left(\sqrt[3]{64}-\left(2\right)\left(2\right)\right)-\frac{\left(3\right)^3\left(2\right)}{6}](https://tex.z-dn.net/?f=%5Cleft%28-3%5Cright%29%5E3-%5Csqrt%5B3%5D%7B27%7D-4%5E3%5Cleft%28%5Csqrt%5B3%5D%7B64%7D-%5Cleft%282%5Cright%29%5Cleft%282%5Cright%29%5Cright%29-%5Cfrac%7B%5Cleft%283%5Cright%29%5E3%5Cleft%282%5Cright%29%7D%7B6%7D)



Which gives us -39.
<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height of a ball thrown into the air after t seconds have elapsed is:</u></em>

<em><u>What is the first time, t, when the ball will reach a height of 20 feet?</u></em>
Substitute h = 20

<em><u>Solve by quadractic formula</u></em>




Rounding off we get,
t = 2.08 , t = 0.42
Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds
Answer:
It is b
Step-by-step explanation:
I did the assignment
Answer:
-1/6
Step-by-step explanation:
I put it into an equation. The periods are a result of autocorrect.
6x+3=2
-3. -3
________
6x= -1
--- ---
6. 6
X = -1/6