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sergey [27]
3 years ago
15

When Maria started her career at the age of 24, she deposited $800 into a savings account that earns 8.75% interest compounded s

emiannually. If she
makes no other deposits or withdrawals, find the total amount in the
account when she retires at the age of 65.
a. $11,378.17
b. $26,791.81
c. $27,817.94
d. $209,234.59
Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer: Answer is b

Step-by-step explanation:

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Answer:

3a² + 13ab - 10b²

Step-by-step explanation:

(3a - 2b)(a + 5b)

Each term in each bracket multiplies each term in the other bracket.

3a(a + 5b) -2b(a + 5b)

3a² + 15ab - 2ab - 10b²

3a² + 13ab - 10b²

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What is the equation of a circle with a radius of 7 and centered at point (3, -4)?

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Answer:

your answer will be D. I think :)

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3 years ago
your health insurance premium is 4211 annually if your employer pays 80% and you are paid monlthy how much is deducted from each
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71.83 is taken away from your monthly check. $4,211 - 80% = $842.20.

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3 years ago
Read 2 more answers
A researcher was interested in comparing the resting pulse rates of people who exercise regularly and people who do not exercise
DiKsa [7]

Answer:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, we failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

Step-by-step explanation:

Refer to the attached data.

The Null and Alternate hypothesis is given by

Null hypotheses = H₀: μ₁ = μ₂

Alternate hypotheses = H₁: μ₁ ≠ μ₂

The test statistic is given by

$ t = \frac{\bar{x}_1  - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }  $

Where \bar{x}_1 is the sample mean of people who do not exercise regularly.

Where \bar{x}_2 is the sample mean of people who do exercise regularly.

Where s_1 is the sample standard deviation of people who do not exercise regularly.

Where s_2 is the sample standard deviation of people who do exercise regularly.

Where n_1 is the sample size of people who do not exercise regularly.

Where n_2 is the sample size of people who do exercise regularly.

$ t = \frac{72.7  - 69.7}{\sqrt{\frac{10.9^2}{16} + \frac{8.2^2}{12} } }  $

t = 0.83

The given level of significance is

1 - 0.95 = 0.05

The degree of freedom is

df = 16 + 12 - 2 = 26

From the t-table, df = 26 and significance level 0.05,

t = 2.056 (two-tailed)

Conclusion:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, We failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

4 0
3 years ago
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