Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
6s
Step-by-step explanation:
1. 2s-(-4s)
2. 2s+4s
3. 6s
Step-by-step explanation:
5*(4x+8)=6*(2x+3)
20x+40=12x+18
20x _12x= 18_40
8x = _22
x=_22/8
x= _11/4
78 m long
Correct answe for sure im not lying
Answer:
6 be because 2×3 =6 so B it will be the given answer
