Answer:
The critical value is T = 1.895.
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 6
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.895, which is the critical value.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159
The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
The solution for the given inequality, m < 3 is 2. According to the inequality, the possible values for “m” must be lesser than 3.
Step-by-step explanation:
11 ÷ 20 = 0.55
0.55 × 100 = 55
so 55%
Step-by-step explanation:
step 1. a polynomial must have whole non negative exponents
step 2. A, B, D have negative exponents
step 3. C is a polynomial.
Answer:
0.218
Step-by-step explanation:
If x represents student that study more than one day, then the probability of x will be 78.2%. In other words, out of 1000 student, 782 of them will study more than one day while 218 of them only study for one day or less
The question asking for the probability that a randomly selected student did not study more than one day, which negation of X statement. So the answer will be ~X= 100%- 78.2%= 21.8%= 0.218