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2 years ago

Can y’all help me pls and the other things i posted!!

Mathematics

1 answer:

zhuklara [117]2 years ago

6 0

This answer is going to be X=-5 because you are solving for X in the parentheses.

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A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. What expression can

Dafna11 [192]

Answer:

The answers to the given question are:

i. The equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

ii. The miner's elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e. speed =

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miner's elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed =

⇒ distance = speed x time

= 4 x 44

= 176

distance = - 176 feet

The distance of the miner's elevator after 14 seconds is:

speed =

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus, after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miner's elevator is deeper than that of the equipment.

Step-by-step explanation:

done

4 0

1 year ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$

The modified DE,

$\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0$

is now exact:

$\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}$

So we look for a solution of the form F(x, y) = C. This solution is such that

$\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}$

Integrate both sides of the first condition with respect to x :

$F(x,y) = -e^{-x}y - \dfrac1x + g(y)$

Differentiate both sides of this with respect to y :

$\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C$

Then the general solution to the DE is

$F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}$

5 0

3 years ago

Kelan shaded 0.5 of the rectangle what fraction equals 0.5

andre [41]

The decimal 0.5 represents the fraction 5/10. The decimal 0.25 represents the fraction 25/100. Decimal fractions always have a denominator based on a power of 10. We know that 5/10 is equivalent to 1/2 since 1/2 times 5/5 is 5/10.

6 0

3 years ago

Read 2 more answers

Please help meeeeeeee

strojnjashka [21]

Answer:

Volume of the cylinder = 602.88 square centimeters

Step-by-step explanation:

Given that:

Radius of cylinder = 4 cm

Height of cylinder = 12 cm

Volume of a cylinder is given by the following formula;

Volume = πr²h

Putting π = 3.14, r = 4 and h = 12 in the formula

Volume = 3.14 * (4)² * 12

Volume = 3.14 * 16 * 12

Volume = 602.88 square centimeters

Hence,

Volume of the cylinder = 602.88 square centimeters

5 0

2 years ago

What's the property of x ( x - 5y ) + 2y ( X - 5y)

Rasek [7]

Associative property

8 0

2 years ago