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klio [65]
3 years ago
7

For a big dinner, Vivian needs to attach an extra piece to her dining room table. Without the extra piece, the table is 6 feet l

ong and 3 feet wide. Attaching the extra piece to the table adds x feet to its length.
Pick all the expressions that represent the area of the table with the extra piece.

A. x(6 + 3)
B. 3(6 + x)
C. 18 + 3x
D. 18 + 6x
Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

See Below

Step-by-step explanation:

If you look at the answers, some of them answer the same answer, and some do not. Lets solve them one by one.

A. x(6+3), you multiply "x" using the Distributive Property to all the numbers in the parenthesis. So your new equation is 6x + 3x. Which is 9.

B. 3(6+x), Same thing, using the distributive property, you multiply 3 into the numbers in the parenthesis. Watch Carefully, since you do not want "x" on the right, you flip the equation making it now 3(x + 6)  making your outcome when you multiply, 3x + 18. You can divide this now by 3, do 3 divided by 3x, and 18 divided by 3 and you get 6.

C. For this answer it is the same thing as option B, 6.

D. This answer is able to be divided by, so you take 6, and divide into 18. 18 divided by 6, and 6 divided by 6x. so the answer is 3 = x.

I think personally the answer is B, and C. For it asks to pick all correct answers. And A, and D, are not the same thing.

Hope This helps!

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Choose the domain for which each function is defined
klemol [59]

Answer:

Part 1) f(x)=\frac{x+4}{x} -----> x\neq 0

Part 2) f(x)=\frac{x}{x+4} ----> x\neq -4

Part 3)  f(x)=x(x+4) ----> All real numbers

Part 4) f(x)=\frac{4}{x^2+8x+16} ----> x\neq -4

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

f(x)=\frac{x+4}{x}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

x\neq 0

Part 2) we have

f(x)=\frac{x}{x+4}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

Part 3) we have

f(x)=x(x+4)

Applying the distributive property

f*(x)=x^2+4x

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

f(x)=\frac{4}{x^2+8x+16}

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

x^2+8x+16=0

Remember that

x^2+8x+16=(x+4)^2

(x+4)^2=0

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

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