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Nady [450]
2 years ago
8

I need help please and thank you ;[

Mathematics
2 answers:
Dvinal [7]2 years ago
8 0
The answer is 12+12x


You divide the 3 with both 4’s

3x4=12
3x4x= 12x
GalinKa [24]2 years ago
6 0

Answer:

12 + 12x

Step-by-step explanation:

Given

3(4 + 4x) ← multiply each term in the parenthesis by 3

= 12 + 12x

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Kylie bought pizza for $12.75 for medium drinks Apollo’s pizza define a variable and write an expression to represent the total
ycow [4]
The answer is 15.75 for the total
4 0
3 years ago
Solve for B. <br><br> R = x(A + B)<br><br> B = (R-A)/X<br> B = (A-Rx)/X<br> B = (R-Ax)/X
Ivanshal [37]
R = x(A + B) solve for B
B = (R-A)/X
4 0
3 years ago
Read 2 more answers
Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
PLEASE HELP ME QUICK WILL GIVE BRAINLIEST
maks197457 [2]
This problem can be solved by calculating the area of the figure before removing the triangles, then subtracting the combined area of the triangles.

First, we have to find the area of the original composite figure.  It appears that the figure consists of a 16 ft by 16 ft square with an 8 ft by 8 ft square cut out:

SA = (16*16) - (8*8)

SA = 256 - 64

SA = 192

The ORIGINAL area of this composite figure is 192 ft².  Now we have to find the area of the removed triangles.  Triangle area is found using half base times height.  The base and height of each triangle appears to be 8, so we can plug in :

TA = \frac{1}{2}(b * h)

TA = \frac{1}{2}(8 * 8)

TA = \frac{1}{2}(64)

TA = 32

The area of each triangle is 32 ft².  Finally, we should subtract the 3 triangles' area from the composite figure's area:

SA - 3(TA)

192 - 3(32)

192 - 96

96

The shaded region's area is 96 ft².

6 0
3 years ago
C^1/2+ c^1/3 for c = 64 ( find the value of the expression for the value indicated)
solmaris [256]

Answer:

12

Step-by-step explanation:

(64)^½ + (64)^⅓

(8²)^½ + (4³)^⅓

8 + 4

12

4 0
3 years ago
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