A.
Using the point-slope form:
y - 2 = 4(x - 1)
y = 4x - 2
B.
We plug the point into the equation to see if it is satisfied:
24 = 4(7) - 2
24 = 26; This is not true so the point is not on the ship's path
C.
The slope of this ship's motion is -1/4, which is the negative reciprocal of the first ship's slope. Therefore, the ships are moving in perpendicular to one another.
Answer:
x²-9x+14=0
Step-by-step explanation:
We can use Vieta's formula:
x²-(sum of roots)x+(product of roots)=0
x²-(2+7)x+(2×7)=0
x²-9x+14=0
P=2w+2l
We know that P=90 and l=15 so we can plug in and solve for w:
90=2w+2(15)
90=2w+30
60=2w
30=w
The width is 30.
(you could draw a diagram by labelling the two shorter sides 15 and the other sides w)
Hope this helps!!
C^2 + 11c = 12
c^2 + 2[11/2] c = 12
[c + 11/2] ^2 - [11/2]^2 = 12
[c +11/2]^2 = 12 +[11/2]^2
[c +11/2]^2 = 12 + 121/4
[c +11/2]^2 =[48+121]/4
[c +11/2]^2 = 169/4 ----> This is the resulting equation
Solving it you get:
c + 11/2 = +/- √(169/4)
c + 11/2 = +/- 13/2
c = 13/2 - 11/2 =2/2 = 1 and
c = -13/2 - 11/2 = - 24/2 = -12