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Tju [1.3M]
3 years ago
14

You want a savings account to grow to $5000 in 10 years. If interest is 3.5% compounded continuously, how much should you invest

?
Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

$3523.44

Step-by-step explanation:

5000 = X × e^(3.5/100)(10)

X = 5000 ÷ e^0.35

X = 3523.440449

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How many do all triangles equal
Ratling [72]
If we are talking about degrees they should equal 180
8 0
3 years ago
For each table of values, write an expression that relates the input to the output.
Arlecino [84]

Answer:

x3, +3

Step-by-step explanation:

Each number gets multiplied by 3 and then you add 3.

8 0
3 years ago
A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after
lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of persons who were still employed primarily as engineers  = \frac{111}{200} = 0.555

           n = sample of graduates = 200

           p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                 significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } , 0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } ]

 = [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0
4 years ago
12men or 18women can reap a field in 14 day ,8man and 16women can reap the same field in​
melisa1 [442]

Answer:

Step-by-step explanation:

12 men and 18 women: x1; 14 days; y1

8 men and 16 women: x2; ?; y2

12/18 simplified is equal to 2/3

8/16 simplified is equal to 1/2

This is a direct proportion, thus we can say that:

(1/2*14)/(2/3)=y2

7/(2/3)=10.5 days

I hope this helped you get out of homework trouble :D

OwO

5 0
3 years ago
I WILL GIVE BRAINLIEST, AND THX
bazaltina [42]
4 - (x + 2) < - 3(x + 4) \\ 4 - x - 2 < - 3x - 12 \\ 2 - x < - 3x - 14 \\ (2x < - 14) \div 2 \\ x < - 7
6 0
4 years ago
Read 2 more answers
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