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2 years ago

Pls help plssadasdsadsadasd

Mathematics

1 answer:

EleoNora [17]2 years ago

6 0

Answer:

option B

hope its helpful

make me brainliest plz

sorry if it isn't correct

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Please help. I don't understand how to do these problems.

aivan3 [116]

Answer:

11a. m <1 = 131 12a. m <1 = 42

11b. m <2 = 49 12b. m <3 = 75

11c. m <3 = 131 12c. m <4 = 42

11d. m <4 = 49 12d. m <5 = 63

11e. m <5 = 131 12e. m <6 = 75

11f. m <6 = 49 12f. m <7 = 105

11g. m <8 = 49 12g. m <8 = 75

11h. m <9 = 92 12h. m <10 = 75

11i. m <10 = 88 12i. m <11 = 42

11j. m <11 = 92 12j. m <12 = 138

11k. m <12 = 88 12k. m <13 = 42

11l. m <13 = 92 12l. m <14 = 138

11m. m <14 = 88

11n. m <15 = 92

Step-by-step explanation:

When lines are parallel to each other than:

Corresponding Angles are equal.

Alternate Interior Angles are equal.

Alternate Exterior Angles are equal.

Consecutive Interior Angles add up to 180 degrees.

You can check some math websites for definitions of these angle relationships.

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3 years ago

What is the volume of the right prism?

Serggg [28]

We know that:
$V = l \times w \times h$

Substituting known values, we have:
$V= 4ft \times 4ft \times 15ft$
$V= 240ft^{3}$

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3 years ago

What is the ratio of x=8y

Lemur [1.5K]

Its going to be 8 y= x/8

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3 years ago

Read 2 more answers

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

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2 years ago

Which product is modeled by the number line below?

bagirrra123 [75]

Answer:

2. (-2)(4)

Step-by-step explanation:

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3 years ago