The function will simply get reflected about the y-axis.
Let's approach this through what we know. Since we know that the x values are mirrored, we know that the points in Quadrant I and IV will be reflected over to the negative side, Quadrants II and III, because they simply change in signs.
However, we also know that the function y-values do not change. This is because whatever the x values are don't change the range and y-values of an even function.
To be more specific, if we have an even function, we are most likely dealing with quadratics or variants/transformations of the quadratic function.
If we were to have 2, and -2, and we wanted to plug them into the equation:

, the signs do not change the y-values of the function.
Hence, we know that it ONLY gets reflected across the y-axis.
Answer:
-2(2+5r)
Step-by-step explanation:
-(7+10r)+3
then you remove the parentheses
-7-10r+3
calculate the sum
-4-10r
factor the expression
-2(2+5r)
Answer:
<h3>A (3, 1)</h3>
Step-by-step explanation:
If we have the coordinate (x,y), if this coordinate is rotated by 180 degrees clockwise, the resulting coordinate will be expressed as (-x, -y) i.e the original coordinate axis are both negated.
Given the coordinate C(-3, -1), if this coordinate is rotated clockwise about the origin, the coordinate of the resulting point will be at C' (-(-3), -(-1))
C' (-(-3), -(-1))
C' = (3, 1)
Hence option A is correct
Answer:
55y454t
Step-by-step explanation:
54wwrg