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3 years ago

A retail store during the holiday season sold (18) $400 computers, (11) $500 computers, (7) $600

Mathematics

1 answer:

dezoksy [38]3 years ago

7 0

Answer:

$450

Step-by-step explanation:

A way to find the median of a set of numbers is by listing each number one by one and then slowly crossing out the smallest and biggest number one by one. If you end up with two numbers left, then you take the mean of those numbers. To do that, you add the two numbers and divide it by two.

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D: 11

tensa zangetsu [6.8K]

Dude it keeps saying incorrect when i put the answer bro it says it again

7 0

3 years ago

Simplify. remove grouping sbols and combine like terms

harina [27]

Answer:

$5a^2+12b^2-40b$

Step-by-step explanation:

First distribute the -4 to the 2b and -3b. This leaves you with $5a^2-8b+12b(b+4)$

Now you can distribute the 12b to b and +4. This leaves you with $5a^2-8b+12b^2+48b$

Now you can combine your like terms leaving you with $5a^2+12b^2-40b$ .

3 0

3 years ago

Write the equation of the line through the points (2,4)(-3,-1). write answer in a point slope form

luda_lava [24]

Answer:

The point-slope form would be y - 4 = x - 2

Step-by-step explanation:

In order to find the equation of the line, we first need to find the slope. For that, we use the slope formula.

m (slope) = (y1 - y2)/(x1 - x2)

Now we plug the numbers into the equation.

m (slope) = (y1 - y2)/(x1 - x2)

m (slope) = (4 - -1)/(2 - -3)

m (slope) = 5/5

m (slope) = 1

Now we can use point-slope form along with the slope and either point to write the equation.

y - y1 = m(x - x1)

y - 4 = (x - 2)

3 0

3 years ago

Find the solution to the equation below.<br> 2x^2+3x-20=0

mariarad [96]

Answer:

x = -4, 5/2

Step-by-step explanation:

A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.

A graph is attached. It shows the solutions to be -4 and 5/2.

When factored, the equation becomes ...

(2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)

Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...

x = (-b±√(b²-4ac))/(2a)

x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4

x = {-4, 5/2}

For ax^2 +bx +c = 0, the solutions must satisfy ...

product of solutions is c/a = -20/2 = -10

Only the first and last choices have this product.

sum of solutions is -b/a = -3/2

Only the first choice (-4, 5/2) has this sum.