Answer:
6 + 6 = 12 × 10 = ?? = 132 that would be just guess the other
Answers:
5. x = 1
6. y = 11.5
Step-by-step explanation:
For question 5, you can use power of a point which describes the relationship of two secants intersecting inside a circle. You get the formula:
AC * CD = BC * CE
You can substitute the values you are given to get:
2 * 4 = x * 8
This gives you x = 1
For question 6, you can use another formula in power of a point that describes two secants intersecting in the exterior of a circle. You get the formula:
GH * GJ = GI * GK
Using segment addition postulate, you get:
GJ = GH + HJ = 5 + 16 = 21
GK = GI + IK = 6 + y --> y + 6
Now, substitute into the equation from power of a point:
5 * 21 = 6 * (y + 6)
105 = 6 * (y + 6)
17.5 = y + 6
y = 11.5
A (-12,-8), B(6,-3), C(3,3)
Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
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