3 years ago

Help me pls don’t guess

Mathematics

2 answers:

Anestetic [448]3 years ago

8 0

Answer:

answer is option 2nd it's very easy to try it!!!!!!!

Arisa [49]3 years ago

3 0

Answer:

2 one

cause if you distribute

then you add

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3 years ago

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2 years ago

Number 10 plzz???????

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3 years ago

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

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3 years ago