Hope this is understandable.
Let the 3-digit palindrome be 101a+10b. a+a+ab=8+b, so 2a+ab-b=8.
2a+b(a-1)=8; b=2(4-a)/(a-1). From this we know that a > 1. And we know 4-a > 0 so a < 4.
This limits a to 2 and 3 which make b=4 and 1.
The palindromes are 242 and 313.
Answer:
n=5
Step-by-step explanation:
by using
n=(an-a)/a+1
substituting values
n= 7.2-(-7.2)/3.6 +1
n=5
It.s not correct, but it’s not hard to learn. All you really have to do is multiply both the numerator and the denominator by each of the numerators that are listed in the problem. If you need help just ask, but I’m not going to give you the problem because you can do it! Just ask if you don’t understand.
