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puteri [66]
3 years ago
12

Part A: Create a system of linear equations with no solution. In two or more complete sentences, explain the specific characteri

stics that you included in each equation to ensure that the system would not have a solution.
Part B: Using one of the equations that you created in Part A, create a system of linear equations that has one solution (x, y). Use substitution to solve the system.
Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0
Part A.
You need two equations with the same slope and different y-intercepts.
Their graph is parallel lines. Since the lines do not intersect, there is no solution.

y = 2x + 2
y = 2x - 2

Part B.
We use the first equation as above. For the second equation, we use an equation with different slope. Two lines with different slopes always intersect.

y = 2x + 2
y = -2x - 2

In the second equation, y = -2x - 2. We now substitute -2x - 2 for y in the first equation.

-2x - 2 = 2x + 2

-4x = 4

x = -1

Now substitute -1 for x in the first equation to find y.

y = 2x + 2

y = 2(-1) + 2

y = -2 + 2

y = 0

Solution: x = -1 and y = 0
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Answers are below

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x     y

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