Answer:
19 m
Step-by-step explanation:
This is Geometric progression with
![\left \{ {{u_1=1,\: u_2 =2} \atop {u_n=2^{n-1}u_1} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bu_1%3D1%2C%5C%3A%20u_2%20%3D2%7D%20%5Catop%20%7Bu_n%3D2%5E%7Bn-1%7Du_1%7D%20%5Cright.)
Then the fomular of sum is
![S=u_1\frac{2^n-1}{2-1} =1\times(2^n-1)=2^n-1\\To\: save\: 1 \:million\: then \; our \:sum \: will \: be\: 1000000\\Hence,\\2^n-1=1000000\\2^n=1000001\\n=log_{2}{1000001}\approx19,9\\Thus, it\:would \;be \:19 \:months \:before\: we\: saved \:1000000 \:pounds](https://tex.z-dn.net/?f=S%3Du_1%5Cfrac%7B2%5En-1%7D%7B2-1%7D%20%3D1%5Ctimes%282%5En-1%29%3D2%5En-1%5C%5CTo%5C%3A%20save%5C%3A%201%20%5C%3Amillion%5C%3A%20then%20%5C%3B%20our%20%5C%3Asum%20%5C%3A%20will%20%5C%3A%20be%5C%3A%201000000%5C%5CHence%2C%5C%5C2%5En-1%3D1000000%5C%5C2%5En%3D1000001%5C%5Cn%3Dlog_%7B2%7D%7B1000001%7D%5Capprox19%2C9%5C%5CThus%2C%20it%5C%3Awould%20%5C%3Bbe%20%5C%3A19%20%5C%3Amonths%20%5C%3Abefore%5C%3A%20we%5C%3A%20saved%20%5C%3A1000000%20%5C%3Apounds)
Answer:
A. Square
Explanation:
The square with sides: x+1
Has an area of: (x+1)^2
The rectangle with sides: x+2 and x
Has an area of: x(x+2)
So we simplify the square: (x+1).(x+1)= x^2+2x+1
Simplifying the rectangle: x^2+2x
Therefore the square area is larger by one unit.
Hope you get it!
Answer:
Therefore, the volume of larger cone is
Therefore, the volume of waffle cone is
Therefore, the volume of waffle cone is more than regular ice-cream cone
Step-by-step explanation:
The length of one side of the canvas is approximately
![10.63 $ in$](https://tex.z-dn.net/?f=10.63%20%24%20in%24)
.
Because the canvas is a square, both its length and width should be the same. The area of a square is just the measure of a side, squared.
Since the area is given,
![113 $ in$^2](https://tex.z-dn.net/?f=113%20%24%20in%24%5E2)
, all you need to do is find a number that, when squared, is
![113](https://tex.z-dn.net/?f=113)
.
You can find this number by taking the square root of
![113](https://tex.z-dn.net/?f=113)
. This will give you:
![\sqrt{113} \approx 10.6301458 \approx 10.63](https://tex.z-dn.net/?f=%20%5Csqrt%7B113%7D%20%5Capprox%2010.6301458%20%5Capprox%2010.63)
...which is the approximate length of a side of the canvas.
Some equal or equivalent fraction for 18/81 are as follows:
2/9 = 4/18 = 6/27 = 8/36 = 10/45 = 12/54 = 14/63 = 16/72 = 18/81 = 20/90 = 22/99 = 24/108 = 26/117 = 28/126 = 30/135 = 32/144 = 34/153 = 36/162 = 38/171 = 40/180.