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3 years ago

What is the intersection of the sets A = {3, 4, 7, 8, 13} and B= {3, 7, 10, 13, 17}

2 answers:

8 0

This intersection means that u have to find the same number in both sets

the answer is 3 , 7 , 13

i am a mathematics teacher. if anything to ask please pm me

kipiarov [429]3 years ago

3 0

I think its seven. not 100%

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Which of the following are solutions to the system graphed below.

Kisachek [45]

Weird. I think you just need to look if the point falls on the shaded area. But only (-5,5) does ...

4 0

3 years ago

Can someone explain how to do "interquartile range"

Andrews [41]

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

7 0

2 years ago

Read 2 more answers

At Southside Middle School, 20% of the students play an instrument. There are 305 students. How many students play an instrument

stellarik [79]

61 students

.2x305= 61

4 0

3 years ago

Read 2 more answers

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

The number m and 58 are additive inverses. Drag and drop 58 and m to their correct positions on the number line.

Elodia [21]

The additive inverse is a number, when added to another number, yields 0.
Its basically the opposite number.....same number, different sign.

so if the number m and 58 are additive inverses, then m = -58 <==

because -58 + 58 = 0

8 0

3 years ago