All categories

2 years ago

100 POINTS IF U GET THIS RIGHT!

Mathematics

2 answers:

Nastasia [14]2 years ago

5 0

Answer:

${ \mathfrak{ mixed \: fraction{ \rm{ : \: 8 \frac{1}{2} }}}} \\ \\ { \mathfrak{ improper \: fraction{ \rm{ : \: \frac{17}{2} }}}}$

Step-by-step explanation:

• General equation of a line is given as below

${ \boxed{ \rm{y = mx + b}}}$

m is the slope
b is the y-intercept

• By relation with the equation given,

${ \rm{m = \frac{17}{2} }}$

iVinArrow [24]2 years ago

3 0

Answer:

That is the answer

Hope this helps!

You might be interested in

What is the solution to the system of equations?

Llana [10]

Solution in attachment.

3 0

3 years ago

Write <br> 46.017<br> as a mixed number.

ddd [48]

17 is in the thousandths place, so we write it as a fraction over 1000.

17/1000

So we have:

46 17/1000

8 0

2 years ago

Read 2 more answers

How long does it take for an investment to quadruple in value if it is invested at 11% compounded

defon

Let's assume we have $100 and an interest rate of 7%. For the $100 to quadruple it means that the future value would be $400. Thus, because we are talking about compounding daily we will set us the equation as follows:

100 * (1+1.07)x = 400

Then we will take 400 and divide it by 100 getting:

1.07X = 4

Now we have encountered a problem where we do not know exponent, so we will use logarithm to calculate such and transform our equation to: Log1.07(4)=X

Using our calculator we will find that it takes about 20.4895 days to quadruple the money invested under 7% interest rate compounded daily.

2nd: Using the same $100 but with the rate of 5.5% compounded continuously we will be using A=PERT formula

where:

P (principal) is equal to hypothetical $100

E (e) is a mathematical constant, which is approximately 2.718

R (rate) is the interest rate, in our case it is 5.5%

T (time) is the time required for money to grow

A (amount) is the final amount desired, which is 4 times larger of $100, thus $400

We have the following:

400 = 100 * e0.055t

400/100 = e0.055t

4 = e0.055t

Then we will apply natural log to both sides of the equations and get the following:

ln(4) = ln(e0.055t)

Since e is the base of ln(x) the equation simplifies to:

ln(4) = 0.055t

Using the calculator to find ln(4) we are getting:

1.38629 = 0.055t

Lastly find t

t = 1.38629/0.055

t = 25.20535202

Plug the answers back to the original equation to verify the answers.

1st part of the question answer: t = 20.4895

2nd part of the question answer: t = 25.20535202

3 0

2 years ago

A pear costs x cents. An orange costs y cents less

VARVARA [1.3K]

Step-by-step explanation:

Pear cost=x

Orange cost=x-y

4 pears= 4x

6 oranges=6x-6y or x-y x6

Use ratio.

Pears: x cents

4 Pears: 6x cents

You x4 on each side. Same with oranges.

Orange: x-y

6 oranges: x-y x6

You x6 on each side.

8 0

2 years ago

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

3 years ago