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sweet [91]
3 years ago
11

A football team has a squad of 24 players,

Mathematics
2 answers:
Anettt [7]3 years ago
5 0

Answer:

1/3.

Step-by-step explanation

1/12 * 24 = 2 players suspended leaving 22 players.

So the number injured = 22 - 14 = 8.

Fraction injured = 8/24 = 1/3.

lora16 [44]3 years ago
4 0
Answer: 1/3

Explanation:

1/12 of the squad are suspended:

1/12 x 24 = 24/12 = 2

So 2 player are suspended

24 - 2 = 22 player

And some are injured leaving 14 left to play:

22 - 14 = 8 players injured

So 8/24 is the fraction of injured player.

But 8/24 = 1/3 so we can say 1/3 of the whole squad are injured.
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Mila [183]

Answer:

i hope its right

Step-by-step explanation:

give me brainliest answer.

4 0
2 years ago
URGENTEE. NON SO RISOLVERE QUESTO PROBLEMA.
Marrrta [24]

the question in English


Draw a rectangle having the base congruent to the nine sevenths of the height.

Let

b-------> the base of rectangle

h-------> the height of rectangle

we know that

b=(9/7)*h-------> this is the equation to obtain the base of the rectangle for a given height

examples

1) for h=7 units

b=(9/7)*7-------->b=9 units

the dimensions are 9 units x 7 units------> see the attached figure

2) for h=5 units

b=(9/7)*5-------->b=(45/7) units

the dimensions are (45/7) units x 5 units

The answer in Italian

Facciamo

b-------> base del rettangolo

h-------> altezza del rettangolo

Noi sappiamo che

b=(9/7)*h-------> questa è l'equazione per ottenere la base del rettangolo per una determinata altezza

esempi

1) per h=7 units

b=(9/7)*7-------->b=9 units


le dimensioni sono 9 units x 7 units-----> vedere la figura allegata

2) per h=5 units

b=(9/7)*5-------->b=(45/7) units


le dimensioni sono (45/7) units x 5 units

4 0
3 years ago
The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
What 3.405 ounces in expanded form
Y_Kistochka [10]
What you’re doing is breaking it down into its parts and writing it into an equation that way long hand.

3 + .4 + .00 + .005
7 0
3 years ago
Write $\frac{99}{100}\cdot(0.\overline{4})$ as a fully simplified fraction.
Oksi-84 [34.3K]

Answer:

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Explanation:

The expression that must be rewritten as a fully simplified fraction is:

  • \frac{99}{100}\cdot(0.\overline{4})

You must, first, convert     0.\overline{4}    as a fraction.

The line over the decimal 4 means that the digit 4 repeats indefinetly.

To find the fraction that represents this number you follow this procedure:

F=0.\overline 4\\ \\ 10F=4.\overline 4\\ \\ 10F-F=4\\ \\ 9F=4\\ \\ F=4/9

Now, you can mutiply both fractions:

\frac{99}{100}.\frac{4}{9}=\frac{99\times 4}{100\times9}=\frac{11}{25}

6 0
3 years ago
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