(NO LINKS) Please help this assignment is over due and I don't get it thx ;)

Help I only have 15 minutes -2 = 12x + 22

otez555 [7]

Answer:

x = -1

you're welcome bud.

3 0

4 years ago

Read 2 more answers

12. (07.06 LC) A library building is in the shape of a rectangle. Its floor has a length of (3x + 5) meters and a width of (5x −

Goshia [24]

ANSWER

$15 {x}^{2} + 22x - 5$

EXPLANATION

It was given that, the length of the rectangular building is

$(3x + 5) \: meters$

and the width of the is

$(5x - 1) \: meters$

The area of a rectangular building is calculated using the formula for finding the area of a rectangle.

$A = l \times w$

Since the dimensions are given in terms of x, the area is also a function of x,

$A(x) = (3x +5 )(5x - 1)$

We expand to get,

$A(x) = 3x(5x - 1) + 5(5x - 1)$

$A(x) = 15 {x}^{2} - 3x + 25x - 5$

$A(x) = 15 {x}^{2} + 22x - 5$

meters square

8 0

4 years ago

Scott started his banking account with $150 and is spending $7 per day on lunch what would the x axis be labeled

Mariulka [41]

X: number of days
y: money available

8 0

3 years ago

Really need help with this pls help!!

worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as the area of some shape.

x² (read as "x squared") can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a rectangle with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about perfect squares. More specifically, we're looking for something to add on that'll make this thing a perfect square. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is complete this square, to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1 = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.