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3 years ago

Make v the subject of the formula

Mathematics

2 answers:

EleoNora [17]3 years ago

7 0

$T =\dfrac 5{V+1}\\\\\\\implies VT+T = 5\\\\\implies VT = 5-T\\\\\implies V =\dfrac{5-T}T$

Mariana [72]3 years ago

7 0

<h2>Answer: $V = \frac{5}{T} - 1$ OR $V = \frac{5 - T}{T}$ </h2>

Step-by-step explanation:

One way we can make V the subject of the formulas by rearranging the terms mathematically to get V on one side of the equation and the other terms on the other side:

since T = 5 ÷ (V + 1) [multiply both sides by (V+1)]

T (V + 1) = 5 [divide both sides by T]

(V + 1) = 5 ÷ T [subtract 1 from both sides]

V = (5 ÷ T) - 1 OR $V = \frac{5}{T} - 1$

If we want the RHS with over a single denominator we can write it as

V = (5 ÷ T) - (T ÷ T) [rewrite 1 in terms of T (T/T)]

V = (5 - T) ÷ T OR $V = \frac{5 - T}{T}$

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Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

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$0.842 = \frac{X - 330}{12}$

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