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3 years ago

Please help me I will give u brainless pls pls I’m begging you

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Solution (part 1-original): a=8 cm^2, b=3 cm^2, c=15 cm^2

Step by step solution:
The way you find area of a parallelogram is base times height so in A it would be 2x4 so 8 cm^2. You need to add the unit and have it squared to show that it’s representing a 2d space instead of a length

Solution (part 2-enlarged): a=32 cm^2, b=16 cm^2, c=60cm^2

Step by step solution (part 2):
It’s basically the same as before except that you multiply the side lengths by 2 BEFORE multiplying the height and base. So a would be (2x4)x(2x2) or 8x4=32.

You might be interested in

I need help with this ASAP and can you explain so i can understand?!

Elanso [62]

Answer:

Adult tickets sold = 225

Student Tickets sold = 375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

$x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)$

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

$We\:have\\x+y=600\\x=600-y$

Put in eq(2)

$6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375$

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

$x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225$

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0

3 years ago

Read 2 more answers

Create an equivalent expressions for each of the following.

Sphinxa [80]

Hope this helps.

4 0

4 years ago

Read 2 more answers

A machine produces small cans that are used for baked beans. The probabil- ity that the can is in perfect shape is 0.9. The prob

Elis [28]

Answer:

0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Shipped for use

Event B: Perfect shape

Probability of being shipped for use:

Perfect shape(0.9 probability) or unnoticeable dent(0.02 probability). So

$P(A) = 0.9 + 0.02 = 0.92$

Being shipped for use and being in perfect shape.

0.9 probability, so $P(A \cap B) = 0.9$

What is the probability that a can that gets shipped for use will be of perfect shape?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.9}{0.92} = 0.9783$

0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape

8 0

3 years ago

you start with a given set of rules and conditions and determine something to be true. What type of reasoning did you use?

sergij07 [2.7K]

Answer:

Deductive Reasoning.

Step-by-step explanation:

Basically it’s logical thinking in simply terms.

5 0

3 years ago

A sample has a mean of M = 90 and a standard devia-tion of s 20.=a. Find the z-score for each of the following X values.X = 95X

sladkih [1.3K]

Answer:

$\begin{gathered} X=95,z=0.25 \\ X=80,z=-0.5 \\ X=98,z=0.4 \\ X=88,z=-0.1 \\ X=105,z=0.75 \\ X=76,z=-0.7 \end{gathered}$

Explanation:

Given a sample with the following:

• Mean,M = 90

• Standard deviation, s = 20

To find the z-score for each of the given X values, we use the formula below:

$\begin{equation*} z-score=\frac{X-\mu}{\sigma}\text{ where }\begin{cases}{X=Raw\;Score} \\ {\mu=mean} \\ {\sigma=Standard\;Deviation}\end{cases} \end{equation*}$

The z-scores are calculated below:

$\begin{gathered} \text{When X=95, }z=\frac{95-90}{20}=\frac{5}{20}=0.25 \\ \text{When X=80, }z=\frac{80-90}{20}=\frac{-10}{20}=-0.5 \\ \text{When X=98, }z=\frac{98-90}{20}=\frac{8}{20}=0.4 \end{gathered}$ $\begin{gathered} \text{When X=88,}z=\frac{88-90}{20}=\frac{-2}{20}=-0.1 \\ \text{When X=105, }z=\frac{105-90}{20}=\frac{15}{20}=0.75 \\ \text{When X=76, }z=\frac{76-90}{20}=\frac{-14}{20}=-0.7 \end{gathered}$

5 0

1 year ago