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3 years ago

Create an equivalent expressions for each of the following.

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

-6 ( 10x-4) Use the distributive law:-

= -60x + 24

(-y+5.3)+ (7.2y -9) First remove parentheses:-

= -y + 5.3 + 7.2y - 9 Now add like terms:-

= 7.2y - y -9 + 5.3

= 6.2y - 3.7

5-8(4-1v +3v)

= 5 - 32+ 8v - 24v

= -27 - 16v

-10 ( 3+ 10v) -9v

= -30 - 100v - 9v

= -30 - 109v

30/45G + 20) - ( 8/9G + 7) Converting:- 8/9G = 40/45G :-

= 30/45G - 40/45G + 20 - 7

= -10/45G + 13

= -2/9G + 13

Sphinxa [80]3 years ago

4 0

Hope this helps.

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3 years ago

Mark is going to an awards dinner and wants to dress appropriately. He has one blue dress shirt, one white dress shirt, one blac

dlinn [17]

Solution:

Outfit Shirt Slacks Tie

Outfit 1 Blue Black Red

Outfit 2 Blue Grey Red

Outfit 3 White Black Red

Outfit 4 White Grey Red

Outfit 5 Black Black Red

Outfit 6 Black Grey Red

We take the outfits 1, 2 , 5 and 6 as a subset of the sample space.

So these 1, 2, 5 and 6 consists either a blue shirt or a black shirt.

The subset consists of all the outfits that do not have a white shirt.

So the correct options are :

1. (Choice A)

The subset consists of all the outfits that do not have a white shirt.

2. (Choice C)

The subset consists of all the outfits that have a black shirt.

5 0

2 years ago

Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

$b_{11}+15=1\Rightarrow b_{11}=-14$

$b_{12}-7=2\Rightarrow b_{12}=9$

$b_{13}+4=12\Rightarrow b_{13}=8$

$b_{21}+0=4\Rightarrow b_{21}=4$

$b_{22}+1=0\Rightarrow b_{22}=-1$

$b_{23}+2=2\Rightarrow b_{23}=0$

Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

3 0

2 years ago

What’s the gcf of 89 and 64

sergij07 [2.7K]

The greatest common factor is 1

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3 years ago

Read 2 more answers

X + 3 = -1 Prove x<br> Need help I need to see work. Don’t understand this problem.

raketka [301]

Answer:

x=-4

Step-by-step explanation:

X needs to be a number that when 3 is added to it, becomes -1. So, adding 3 to -4 gives you -1, therefore, x=-4. Hope this helped!

8 0

2 years ago