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Yuki888 [10]
2 years ago
12

Can someone explain this

Mathematics
1 answer:
postnew [5]2 years ago
7 0

Step-by-step explanation:

n-4≥13

n≥13+4

n≥17

point the no. 17 in the number line.

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Olivia and her three siblings bring a sack lunch to school each day, consisting of a bagel, an apple, a cookie, and a juice box.
pogonyaev

Answer:

72/4=18 so she could make their lunch for 18 days

Step-by-step explanation:

so it would be 6x12 for the bagels which would be 72

for the apples it would be 8x9 which is 72

the cookies would be 12x6 to get 72

and the juice boxes would be 9x8 to get 72

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A machinist can produce 12 parts in 40 min.how many parts can the machinist produce in 4 hours?
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Answer:

72 parts

Steps:

Convert the 4 hours into minutes. There are 60 minutes in an hour. Therefore, 4 hours = 240 minutes.

Divide 240 minutes by 40 minutes. This equals 6. Therefore, the machinist can produce the 12 parts 6 times in 4 hours.

Finally, multiply the 12 parts by the 6 times he can produce. Therefore, the machinist can produce 72 parts in 4 hours.
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Step-by-step explanation:

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A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

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A customer who sends 78 messages per day would be at 99.38th percentile.

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