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erik [133]
2 years ago
15

F (x) is an exponential function with these features: f (x) is increasing, the y-intercept is (0,1), and f (2) = 49. Which

Mathematics
1 answer:
aleksley [76]2 years ago
8 0

Answer:

Hi how are you!

Step-by-step explanation:

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Can someone help me? I know I'm doing something wrong but I'm not sure what.
Natasha2012 [34]

Answer:

Step-by-step explanation:

CI = 624 x 1.05 ^3 =722.358 for whole investment   722.36-624 =98.36 for interest only

or for interest only do 624 x .05^3 = 98.36

Standard interest is done like this

year 1 = 624 x 1.05 = 655.20

655.20-624 = 31.20

year 2 = 655.20 + 31.20 = 686.40

year 3 = 686.40 + 31.20 = 717.60

total interest = 717.60-624 = 93.60

So standard interest is the method you have done they may be asking for either compound interest which is the first one or asking for whole investment which means you need to also add 624 at end for Standard interest.

if you need CI interest do the top one.

8 0
2 years ago
A man has 1 coins in his pocket, all of which are dimes and quarters. Aif the total value of his change is $2.75, how many dimes
VLD [36.1K]

Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of dimes in his pocket.
  • Variable y: number of quarters in his pocket.

He has a total of 14 coins, hence:

x + y = 14 -> y = 14 - x.

They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:

0.1x + 0.25y = 2.75

Since y = 14 - x:

0.1x + 0.25(14 - x) = 2.75

x = (0.25*14 - 2.75)/0.15.

x = 5.

y = 14 - x = 14 - 5 = 9.

There are 5 dimes and 9 quarters in his pocket.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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1 year ago
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Aleksandr-060686 [28]
The temperature would be -10 degrees
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I need the attachment that goes with it


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