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dsp73
2 years ago
10

You are playing a game where you draw a card from a standard deck, and you will win $13 if you draw a face card,

Mathematics
1 answer:
marissa [1.9K]2 years ago
8 0

Answer:

Step-by-step explanation:

win

There are 3 face cards / suit. Every suit contains a Jack, Queen, and king.

There are 4 suits so the number of face cards is 3*4 =  12

There is 1 ace / suit

There are 4 suits so the number of aces is 1 * 4 = 4

The gain from the face cards = 12 * 13 = 156

The gain from the aces = 4 * 3 =               12

Total gain = 168

Losses

Any other card costs you $5

How many cards is that? 52 - 16 = 36

Each one costs 5 dollars

Total loss = 5 * 36 = 180

So each time you play the game, you can expect to lose 180 - 68 = 12 dollars. You should walk away quickly from this one.

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Is there any way that someone can get PYGRO attention plz I need to talk to him
Alla [95]

Answer:

who

Step-by-step explanation:

3 0
2 years ago
A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec
Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

CI=\bar x\pm z_{\alpha/2}\times SE

For 5% level of significance the two tailed critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct the 95% confidence interval as follows:

CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0
3 years ago
Read 2 more answers
11) a - 15 &gt;-40-6 + 3a)<br>​
SOVA2 [1]

Answer:

a < \frac{31}{2}

Step-by-step explanation:

Given

a - 15 > - 40 - 6 + 3a ← simplify right side

a - 15 > - 46 + 3a ( subtract a from both sides )

- 15 > - 46 + 2a ( add 46 to both sides )

31 > 2a ( divide both sides by 2 )

\frac{31}{2} > a ⇒ a < \frac{31}{2}

4 0
3 years ago
Anyone know the answer?
ANTONII [103]
PKE is a triangle and its interior angles therefor sum to 180deg:

P+K+E=180
90+(x+6)+2x=180
96+3x=180
3x=84
x=\frac{84}{3}=28deg
5 0
4 years ago
What is 8×9÷6+2-8.53²+⅖​
denpristay [2]

8×9÷6+2-8.53²+⅖​

= -58.3609

3 0
3 years ago
Read 2 more answers
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