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alexandr402 [8]
2 years ago
15

The density of a substance is the mass of the substance per unit of volume. The density of the element Americium is inversely pr

oportional to its volume. The graph shows the relationship between the density of Americium, p grams per cubic centimeters, and its volume, v cubic centimeters.
Mathematics
1 answer:
Viktor [21]2 years ago
7 0

Answer:

(3,4)

Step-by-step explanation:

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The same garden shop sells mulch according to the equation y = 20x, where y represents the cost in dollars, and x represents the
romanna [79]

Answer:

Mulch costs $10 more per cubic yard than topsoil.

Step-by-step explanation:

Got 100% on this Test/Usa

4 0
3 years ago
Read 2 more answers
The ages of two brothers are in the ratio two to three, but in eight years, the ratio of their ages will be three to four. What
grigory [225]
3(3x+8)=4(2x+8)
9x+24=8x+32
x=8

2(8)=16
3(8)=24
 
that means that the younger brother is 16 years old 
8 0
3 years ago
The length of a rectangle is 9 cm more then half the width. Find the length of the perimeter is 60cm
stira [4]

length = 1/2 w+9

perimeter= 60 =2(l+w)  

substitute in for length

60 = 2(1/2 w +9 +w)  

60 = 2 (3/2 w +9)

distribute

60 = 3w + 18

subtract 18 from each side

42 = 3w

divide by 3 on each side

14 = w

length = 1/2 w + 9

length = 1/2 (14) +9

              7 + 9

16cm

7 0
3 years ago
Simplify.<br> +6 - 4 =<br><br><br> please help ..........
Step2247 [10]

Answer:

2

Step-by-step explanation:

it's literally 6-4 = 2

8 0
3 years ago
Read 2 more answers
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
4 years ago
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