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1 year ago

0.27 recurring as a fraction please

Mathematics

2 answers:

Ilia_Sergeevich [38]1 year ago

8 0

Answer:

Jimrgrant1 has already answered this correctly, 3/11.

Step-by-step explanation:

I took 1.0 and divided it by 0.272727 to give 3.666666 . . .

I looked for value that would convert this into a whole number when multiplied. 3 times 3.666666 . . . is equal to 11.

That would mean a fraction equal to 0.272727 . . . would be 3/11

natali 33 [55]1 year ago

3 0

Answer:

$\frac{3}{11}$

Step-by-step explanation:

assuming the recurring digits are 0.272727.... , then

we require 2 equations with the repeating digits placed after the decimal point.

let x = 0.2727.... (1) ← multiply both sides by 100

100x = 27.2727... (2)

subtract (1) from (2) thus eliminating the repeating digits

99x = 27 ( divide both sides by 99 )

x = $\frac{27}{99}$ = $\frac{3}{11}$ ← in simplest form

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2 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

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Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

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Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

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So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

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2 years ago

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2 years ago

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Answer:

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2 years ago

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shtirl [24]

Answer:

Step-by-step explanation:

Figure (1)

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2 years ago