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Tpy6a [65]
2 years ago
15

The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da

y. There are 3.65 \cdot 10^23.65⋅10 2 3, point, 65, dot, 10, start superscript, 2, end superscript days in one year. How many times does the heart beat in one year?
Mathematics
2 answers:
andriy [413]2 years ago
4 0

Answer:

4.1975\cdot 10^{7}

Step-by-step explanation:

We are told that the average human heart beats 1.15\cdot 10^{5} times per day and there are 3.65\cdot 10^{2} days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

1.15\cdot 10^{5}\times 3.65\cdot 10^{2}

Now we will solve this problem using exponent properties.

1.15 \times 3.65\cdot 10^{2+5}

1.15 \times 3.65\cdot 10^{7}

4.1975\cdot 10^{7}

Our answer is in scientific notation we can represent it in standard form as 4.1975\cdot 10^{7}=4.1975*10000000=41975000 times.

Therefore, average human heart beats in one year 4.1975\cdot 10^{7} or 41975000 times.

Lesechka [4]2 years ago
3 0

Answer:

4.2*10^7

Step-by-step explanation:

Khan Academy

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