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2 years ago

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The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da

y. There are 3.65 \cdot 10^23.65⋅10 2 3, point, 65, dot, 10, start superscript, 2, end superscript days in one year. How many times does the heart beat in one year?

2 answers:

andriy [413]2 years ago

4 0

Answer:

$4.1975\cdot 10^{7}$

Step-by-step explanation:

We are told that the average human heart beats $1.15\cdot 10^{5}$ times per day and there are $3.65\cdot 10^{2}$ days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

$1.15\cdot 10^{5}\times 3.65\cdot 10^{2}$

Now we will solve this problem using exponent properties.

$1.15 \times 3.65\cdot 10^{2+5}$

$1.15 \times 3.65\cdot 10^{7}$

$4.1975\cdot 10^{7}$

Our answer is in scientific notation we can represent it in standard form as $4.1975\cdot 10^{7}=4.1975*10000000=41975000$ times.

Therefore, average human heart beats in one year $4.1975\cdot 10^{7}$ or 41975000 times.

Lesechka [4]2 years ago

3 0

Answer:

4.2*10^7

Step-by-step explanation:

Khan Academy

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Step-by-step explanation:

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$\angle NOF = \angle MOD = \angle MOF = \angle FOD = 90^{\circ}$ (By definitions of complementary and vertical angles and the theorem that states that sum of internal angles within a triangle equals 180º)

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$MK = \frac{MD-NF}{2}$

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$A_{AMNFD} = NK\cdot (NF+MK)$

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