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Tpy6a [65]
2 years ago
15

The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da

y. There are 3.65 \cdot 10^23.65⋅10 2 3, point, 65, dot, 10, start superscript, 2, end superscript days in one year. How many times does the heart beat in one year?
Mathematics
2 answers:
andriy [413]2 years ago
4 0

Answer:

4.1975\cdot 10^{7}

Step-by-step explanation:

We are told that the average human heart beats 1.15\cdot 10^{5} times per day and there are 3.65\cdot 10^{2} days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

1.15\cdot 10^{5}\times 3.65\cdot 10^{2}

Now we will solve this problem using exponent properties.

1.15 \times 3.65\cdot 10^{2+5}

1.15 \times 3.65\cdot 10^{7}

4.1975\cdot 10^{7}

Our answer is in scientific notation we can represent it in standard form as 4.1975\cdot 10^{7}=4.1975*10000000=41975000 times.

Therefore, average human heart beats in one year 4.1975\cdot 10^{7} or 41975000 times.

Lesechka [4]2 years ago
3 0

Answer:

4.2*10^7

Step-by-step explanation:

Khan Academy

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(5+4-2)×(-2)=idfkadtsphm
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5+4=9   9-2=7 

7x(-2)= (-14)

your answer is -14

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3 years ago
How did the temperature change if: at first it decreased by 10 % and then decreased by 30% ?
MAVERICK [17]

Answer:

Decreased by 40%!

Step-by-step explanation:

At first it goes down by 10%, then 30%, so you just add them together and get decreased by 40%.

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Find the slope on the line
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Five over three
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2 years ago
The angle between a diagonal and the longer base of the isosceles trapezoid MNFD is 45°. NK is an altitude to the longer base. I
Elanso [62]

Answer:

NK \approx 7.001, MK = 2, MF \approx 7.001, A_{AMNFD} = 49.007

Step-by-step explanation:

According to the statement, we find the following inputs:

\angle MDK = \angle DMF = 45^{\circ} (Due to the condition of isosceles trapezoid)

MD = 9

NF = 5

Given than longer base and shorter base are parallel to each other, we conclude that:

\angle KND = 180^{\circ} -\angle NKD - \angle KDN

\angle KND = 180^{\circ}-90^{\circ}-45^{\circ}

\angle KND = 45^{\circ}

\angle FND = 90^{\circ}-\angle KND

\angle FND = 45^{\circ} (By definition of complementary angles)

\angle FND = \angle NFM = 45^{\circ} (Due to the condition of isosceles trapezoid)

\angle MDK = \angle DMF = \angle FND = \angle NFM = 45^{\circ}

\angle NOF = \angle MOD = \angle MOF = \angle FOD = 90^{\circ} (By definitions of complementary and vertical angles and the theorem that states that sum of internal angles within a triangle equals 180º)

MO = DO = \frac{\sqrt{2}}{2}\cdot MD (By theorem for 45-45-90 Right Triangle)

NO = OF = \frac{\sqrt{2}}{2}\cdot NF (By theorem for 45-45-90 Right Triangle)

If we know that MD = 9 and NF = 5, then we find that:

DO = MO \approx 6.364

NO = OF \approx 3.536

The value of MK is obtained from the following relationship:

MK = \frac{MD-NF}{2}

MK = \frac{9-5}{2}

MK = 2

And the value of KD is calculated from this expression:

KD = MD-MK

KD = 9-2

KD = 7

Now by the Pythagorean Theorem we find that:

NK = \sqrt{(NO+DO)^{2}-KD^{2}}

NK = \sqrt{9.9^{2}-7^{2}}

NK \approx 7.001

And considering the symmetry characteristics of an isosceles trapezoid, we determine MF:

MF = NO + DO \approx 7.001

Lastly, the area of the isosceles trapezoid is determined by the following formula:

A_{AMNFD} = NF\cdot NK + MK\cdot NK

A_{AMNFD} = NK\cdot (NF+MK)

If we know that NK \approx 7.001, NF = 5 and MK = 2, then the area of the figure is:

A_{AMNFD} = (7.001)\cdot (5+2)

A_{AMNFD} = 49.007

8 0
2 years ago
The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function. What is true
kkurt [141]

Answer:

1. Translation 3 units to the right;

2. Reflection across the x-axis;

3. Translation 4 units up.

Step-by-step explanation:

First, rewrite the function g(x) in following way:

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Apply such transformations:

1. Translate the graph of the parent function f(x) 3 units to the right to get the graph of the function f_1(x)=(x-3)^2.

2. Reflect the graph of the function f_1(x) across the x-axis to get the graph of the function f_2(x)=-(x-3)^2.

3. Translate the graph of the function f_2(x) 4 units up to get the graph of the function g(x)=-(x-3)^2+4.

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