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Nastasia [14]
3 years ago
12

Jessica saved a total of $58.50 to spend on school supplies. She wants to buy one backpack for $36.25 and she wants to spend the

rest on folders with paper. Each folder filled with paper costs $3.89. Select the inequality that shows how many folders filled with paper (x) Jessica can buy. A. $36.25+$3.89x≥$58.50 B. $36.25+$3.89x≤$58.50 C. $36.25x+$3.89≥$58.50 D. $36.25x+$3.89x≤$58.50
Mathematics
2 answers:
jenyasd209 [6]3 years ago
5 0

Answer:

$36.25+$3.89x≤$58.50

Step-by-step explanation:

Let x be the number of folders with paper Jessica buys. If Jessica buys x folders for $3.89 each, then she pays $3.89x for all x folders.

She wants to buy one backpack for $36.25, so her total buying costs

$36.25 + $3.89x

Jessica saved a total of $58.50 to spend on school supplies, then her total buying cannot exceed this sum, so  the answer would be $58.50.

Eduardwww [97]3 years ago
4 0

Answer:

B. $36.25+$3.89x≤$58.50

Step-by-step explanation:

It has to be less than or equal to $58.50

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This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

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