Answer:
5.25
Step-by-step explanation:
The fact that the graph crosses the x-axis means the hyperbola opens to the left and right. Hence its equation is ...
x^2/a - y^2/b = 1
The point (-2, 0) helps us find "a":
(-2)^2/a - 0/b = 1
4 = a
Then we can find "b" from the other fully-specified point.
(-3)^2/4 - 4^2/b = 1 . . . . . . substitute (-3, 4) for (x, y)
b = 16/(9/4 -1) = 64/5 . . . . solve for b
Then the third point will satisfy ...
t^2/4 - (5/64)·2^2 = 1 . . . . . . substitute (t, 2) for (x, y)
t^2 = 4·(1 +5/16) = 4 +5/4 . . . . solve for t^2
t^2 = 5.25
The math I used is probably not the quickest way, but for me, the easiest.
25*5=125 25+20=45 45*7=315 125+315=440 25*4=100 440+100=540 5+7+4=16
B is your answer.
Answer:
1 algebraic expression
Step-by-step explanation:
2. constants
Rewrite then factor as a difference of cubes:
1 - 64<em>x</em>³ = 1³ - (4<em>x</em>)³
= (1 - 4<em>x</em>) (1² + 4<em>x</em> + (4<em>x</em>)²)
= (1 - 4<em>x</em>) (1 + 4<em>x</em> + 16<em>x</em>²)
I need the visuals to accurately answer your question. ;-;