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Ipatiy [6.2K]
3 years ago
7

Determine the period of the following graph.

Mathematics
2 answers:
notsponge [240]3 years ago
6 0
The answer is 0 i believe
Alona [7]3 years ago
3 0
0
Because it’s true, and I’m smart
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What’s the perimeter of each of the figures
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The perimeter is the length of the outline of a shape.

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Let v represent the value of a bank acount, in thousands of dollars, t yearsaftertye account is opend at the bank
Liula [17]

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could you explain it more

Step-by-step explanation:

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Helppp please needed before tomorrow!!!!!!!!!!​
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The function is 200+50t (t= # of months)

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The best way to do this is to look at the question, and see no matter what, we have to pay 200 dollars to start. After which, they charge 50 bucks a month. Knowing this, we can make a function using f(x). Let C(t)= cost. Included is that graph. So for these questions, we need to see that there is an independent and a dependent variable, and we need to see that cost is affected by time. Hope this helps.

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2 years ago
WILL MARK BRAINLIEST, I NEED IT ASAP!<br> Find N(A)<br> A= {letters in the word "Strawberry}
Luden [163]

Answer:

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Step-by-step explanation:

hope this is helpful

4 0
3 years ago
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
4 years ago
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