A. Alyssa did not get an A on the math test but rather a B- due to only getting 16 out of the 20 problems right. This can be found out by dividing the amount correct over the total amount of problems.
B. In order for Alyssa to get an A or 90% on her math test she would have had to get two more questions right to have a score of 18 out of 20.
C. In order to figure this question out you have to think that with every incorrect answer that Jessie answered she got three correct along with the one incorrect. By going with that information it can be figured that Jessie's score is 15 correct answers and 5 incorrect information if you go by the ratio 3:1 then go up tell the sides equal up to a total of 20 after being added. So Jessie's score again was 15 out of 20.
Answer:
-3
Step-by-step explanation:
We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:
p(1) = 3(1) - 2 = 1
n(1) = 2(1) - 5 = -3
Then (n/p) (1) = -3/1, or just -3
Answer:
yes it represents the graph accurately
A good place to start is to set
to y. That would mean we are looking for
to be an integer. Clearly,
, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since
is a radical, it only outputs values from
, which means y is on the closed interval:
.
With that, we don't really have to consider y anymore, since we know the interval that
is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval
, which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
It could be solved by analyzing the questions and finding important words that stand out to you. 20=16+4 , 50=10+40. this is the way you find it