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-Dominant- [34]
3 years ago
5

What is the solution of the system of equations? -y+3x=6 y=-6x+12

Mathematics
2 answers:
irinina [24]3 years ago
8 0

Answer:

x = 2

y = 0

Step-by-step explanation:

We can solve using substitution, substitute y in the first equation with the second equation:

-(-6x + 12) + 3x = 6

Distribute the negative sign:

6x - 12 + 3x = 6

Combine like terms:

9x - 12 = 6

Isolate the variable and solve for x by adding 12 in both sides:

9x = 18

x = 2

Substitute 2 with x in any equation to find the value of y:

-y + 3(2) = 6

-y + 6 = 6

Subtract 6 in both sides to isolate the variable:

-y = 0

0/-1 = 0

y = 0

Our answer would be x = 2 and y = 0

Nady [450]3 years ago
7 0

Answer:

(2,0)

Step-by-step explanation:

I'm going to use substitution since one of the variables in one of the equation is already solved for.

-y+3x=6

y=-6x+12

I'm going to replace the first y with the second y which is (-6x+12).

This gives me:

-(-6x+12)+3x=6

Distribute:

6x-12+3x=6

Combine like terms:

9x-12=6

Add 12 on both sides:

9x=18

Divide both sides by 9:

x=2

If x=2 and y=-6x+12, then y=-6(2)+12=-12+12=0.

The solution (the intersection) is (2,0).

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ElenaW [278]
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C. In order to figure this question out you have to think that with every incorrect answer that Jessie answered she got three correct along with the one incorrect. By going with that information it can be figured that Jessie's score is 15 correct answers and 5 incorrect information if you go by the ratio 3:1 then go up tell the sides equal up to a total of 20 after being added. So Jessie's score again was 15 out of 20.
7 0
3 years ago
Read 2 more answers
If p(x) = 3x – 2and n (x) = 2x – 5, what is the value of (n/p) (1)?
Liula [17]

Answer:

-3

Step-by-step explanation:

We want (n/p)(1).  We can obtain this by finding n(1) and p(1) and then dividing as indicated:

p(1) = 3(1) - 2 = 1

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5 0
2 years ago
Please help , write your answer I will be giving 10 points
slamgirl [31]

Answer:

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5 0
2 years ago
For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
Question #2 how do i solve this.
bulgar [2K]
It could be solved by analyzing the questions and finding important words that stand out to you. 20=16+4 , 50=10+40. this is the way you find it
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3 years ago
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