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Tems11 [23]
3 years ago
14

The diameter of a cookie is 2 inches. If pico’s 3.14, what is the area of the cookie, rounded to the nearest 10th?

Mathematics
1 answer:
Amanda [17]3 years ago
6 0

For this case we must find the area of the cookie, knowing that it has a circular shape. By definition, the area of a circle is given by:

A = \pi * r ^ 2

Where:

r: It is the radius of the circle

According to the data we have:

r = \frac {2} {2} = 1 \ in

Thus, the area of the cookie is:

A = \pi * (1) ^ 1

We have \pi = 3.14

A = 3.14 * 1\\A = 3.14

We round:

A = 3.1

Thus, the area of the cookie is 3.1 \ in ^ 2

Answer:

3.1 \ in ^ 2

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The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

<em>49, 56.4, 72.6, 60.1, 65, 64.8, 56.5, 52, 53.2,  </em>

<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

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