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adell [148]
3 years ago
7

I need help solving this for pre calc

Mathematics
1 answer:
Katarina [22]3 years ago
7 0
Starting with:

\frac{2p}{p+1} +  \frac{3}{p-1} =  \frac{15-p}{p^{2}-1}

First, the difference of 2 squares shows that p^{2} - 1 = (p+1)(p-1)

Sub that in and multiply both sides by (p-1)(p+1):

\frac{2p(p+1)(p-1)}{p+1} +  \frac{3(p-1)(p+1)}{p-1} =   \frac{(15-p)(p-1)(p+1)}{(p-1)(p+1)}

This easily simplifies to 2p(p-1) + 3(p+1) = 15 - p

See if you can continue from here. If not, leave a comment and I or someone else can show you the rest.
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