SOLUTION
The question simply means that we should find the sum to infinity of the geometric series.
The formula of sum to infinity of a geometric serie is given by
![S_{\infty}=\frac{a}{1-r}](https://tex.z-dn.net/?f=S_%7B%5Cinfty%7D%3D%5Cfrac%7Ba%7D%7B1-r%7D)
Where
![\begin{gathered} S_{\infty}\text{ is the sum to infinity} \\ \\ a\text{ is the first term = 1} \\ \\ r\text{ is the common ratio = }\frac{2}{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20S_%7B%5Cinfty%7D%5Ctext%7B%20is%20the%20sum%20to%20infinity%7D%20%5C%5C%20%20%5C%5C%20a%5Ctext%7B%20is%20the%20first%20term%20%3D%201%7D%20%5C%5C%20%20%5C%5C%20r%5Ctext%7B%20is%20the%20common%20ratio%20%3D%20%7D%5Cfrac%7B2%7D%7B3%7D%20%5Cend%7Bgathered%7D)
So, this becomes
![\begin{gathered} S_{\infty}=\frac{a}{1-r} \\ \\ S_{\infty}=\frac{1}{1-\frac{2}{3}} \\ \\ S_{\infty}=\frac{1}{\frac{3-2}{3}} \\ \\ S_{\infty}=\frac{1}{\frac{1}{3}} \\ \\ S_{\infty}=3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20S_%7B%5Cinfty%7D%3D%5Cfrac%7Ba%7D%7B1-r%7D%20%5C%5C%20%20%5C%5C%20S_%7B%5Cinfty%7D%3D%5Cfrac%7B1%7D%7B1-%5Cfrac%7B2%7D%7B3%7D%7D%20%5C%5C%20%20%5C%5C%20S_%7B%5Cinfty%7D%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B3-2%7D%7B3%7D%7D%20%5C%5C%20%20%5C%5C%20S_%7B%5Cinfty%7D%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%20%20%5C%5C%20S_%7B%5Cinfty%7D%3D3%20%5Cend%7Bgathered%7D)
Therefore, option b is the correct answer
To find the answer you have to first find how many degrees are there in between each number in the clock. the clock is 360°degrees and there are 12 numbers marked in a clock., so you have to divide 360 by 12 to get the number of degrees in between each number,
360°÷12=30° so there are 30°degrees between each number.
if a clock hand moves from 12 to 5, it pass 5 numbers, so to get your final answer you have to multiply 30° by 5=150°.
so your answer is 150°degrees.
hope you can understand what i said. :)
The GCF is based upon what integer divides evenly into two numbers; the LCM is based upon what integer two numbers share in a list of multiples. The GCF must be a prime number; the LCM must be a composite number.
Answer:
18÷2 × 3 / 5-2
9 ×3 / 3
27/3
9
tyvm this was my 100th answer :)
The two numbers are 5 and 12.