Probability that a student will play both is 7/30
Step-by-step explanation:
Total students = 30
No. of students who play basketball = 18
Probability that a student will play basketball = 18/30
= 3/5
No. of students who play baseball = 9
Probability that a student will play baseball = 9/30
= 3/10
No. of students who play neither sport = 10
Probability that a student will play neither sport = 10/30
= 1/3
To find :
Probability that a student will play both = p(student will play both)
No.of students who play sport = 30 - 10
= 20
Out of 20 students 18 play basketball and 9 play baseball.
So, some students play both the sports.
No. of students who play both sports = 18 + 9 - 20
= 7
p(student will play both) = 7/30
Probability that a student will play both is 7/30
29.98/24≈1.25
2.29-1.25= $1.04
Answer: Children’s Museum $150-$350 per sq. ft. Art Museum Exhibition $75-$200 per sq. ft. (Does not include cost of Art)
Step-by-step explanation:
The distributive property....u r basically multiplying the number outside of the parenthesis by everything inside the parenthesis...this gets rid of the parenthesis.
3(-4x + 8)...distribute the 3 thru the parenthesis
(3 * -4x) + (3 * 8) ...take that 3 and multiply it by every number in the parenthesis..to get rid of the parenthesis
-12x + 24 <===
4(x - 6y) =
(4 * x) - (4 * 6y) =
4x - 24y <===
6(5 - q) =
(6 * 5) - (6 * q) =
30 - 6q <===
1/2(c - 8) =
(1/2 * c) - (1/2 * 8) =
1/2c - 4 <===
-3(5 - b) =
(-3 * 5) - (-3 * b) =
-15 - (-3b) =
-15 + 3b <===
(d + 2)(-7)....re-arrange
-7(d + 2) =
(-7 * d) + (-7 * 2) =
-7d + (-14) =
-7d - 14 <===
