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Hunter-Best [27]
2 years ago
13

Which of the following is a result of shifting a circle with equation

Mathematics
1 answer:
Anna007 [38]2 years ago
6 0

Answer:

Hello,

Answer C

Step-by-step explanation:

x'=x

y'=y+4

(x-1)²+(y-4)²=16

(x'-1)²+(y'-8)²=16

is the circle of center (1,5) and radius 4

<u>The y-coordinate of the center of the circle increases by 4.</u>

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What is the arc length if Θ = 2 pi over 7 and the radius is 3 cm? A. 7 pi over 12
hodyreva [135]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

\theta=\frac{2\pi}{7} \\\\r=3\ cm

An arc is a part of total circumference of circle and length of that arc is the measurement of linear distance.

Since we know the formula for "Length of an arc " , we get

L=r\times \theta\\\\L=\frac{2\pi}{7}\times 3\\\\L=\frac{6\pi}{7}

Hence, Option 'C' is correct.


6 0
3 years ago
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Select two values of x that are roots of this equation (picture included)<br><br> x^2+2x-5=0
WINSTONCH [101]

Step-by-step explanation:

A and C are correct options

7 0
2 years ago
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Determine the x- and y-intercepts of the graph ofx−4y=8Then plot the intercepts to graph the equation.
Over [174]

The x-intercept is the point where the graph cuts the x-axis, and the y-intercept is the point where the graph cuts the y-axis.

The x-axis is the line y = 0 and the y-axis is the line x = 0. To find the intercept between each axis and our graph, we just need to evaluate our function at x = 0 and y = 0.

Calculating the x-intercept, we have

\begin{gathered} x-4\cdot0=8 \\ x=8 \end{gathered}

The x-intercept is (8, 0).

Calculating the y-intercept, we have

\begin{gathered} 0-4y=8 \\ y=-\frac{8}{4} \\ y=-2 \end{gathered}

The y-intercept is (0, -2).

8 0
1 year ago
I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
Please help me I don’t know how to do this and it is due at 10:00 please help
Blizzard [7]

Answer:

number 12 is

\frac{3}{125}

4 0
2 years ago
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