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cluponka [151]
3 years ago
9

Which expression is equivalent to (3a5 + b4)2

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0
Is it multiple choice or do you have to write a answer?
o-na [289]3 years ago
3 0

Answer:

The expression 9a^{10}+6a^2b^4+b^8 is equivalent to the given expression.

Step-by-step explanation:

The given expression is

(3a^5+b^4)^2

Use algebraic formula:

(a+b)^2=a^2+2ab+b^2

(3a^5+b^4)^2=(3a^5)^2+2(3a^5)(b^4)+(b^4)^2

(3a^5+b^4)^2=3^2(a^5)^2+6a^5b^4+(b^4)^2

Use exponent property:

(a^m)^n=a^{mn}

(3a^5+b^4)^2=9a^{10}+6a^5b^4+b^8

Therefore expression 9a^{10}+6a^5b^4+b^8 is equivalent to the given expression.

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3x square+6y Square when X=0 and y=2 with steps pls​
Sauron [17]

Answer:

If the equation is 3x^2+6y^2, when x=0 and y=2.

Then, 3(0)^2+6(2)^2=

So, 0+6(4)= 24

Therefore, the answer is 24.

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP!! Algebra 2 Review !!
Kamila [148]

Answer:

\frac{28-3i}{26}

Step-by-step explanation:

For #2, remember that i=\sqrt{-1}, so i^{2}=-1 Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=a^2-b^2. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number a+bi, where a and b are any numbers, the conjugate is always a-bi. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

\frac{5+6i}{4+6i}=\frac{(5+6i)(4-6i)}{(4+6i)(4-6i)}=\frac{20+24i-30i+36}{16+36}=\frac{56-6i}{52}=\frac{2(28-3i)}{2(26)}=\frac{28-3i}{26}

Our answer is (28-3i)/(26)!

6 0
3 years ago
Can you show me how to do the problem pleaseq
Masteriza [31]

2.0076* 10^4

move the decimal 4 places to the right

20076.

20076 < 26970

5 0
3 years ago
Read 2 more answers
The sum of three consecutive integers is 114. what are the three integers?
RSB [31]

Answer: 37, 38, and 39

Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.

3 consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

X + 2 ⇒ <em>third integer</em>

<em />

Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.

X + X + 1 + X + 2 = 114

We can simplify on the left side by combining the X's and the numbers.

3x + 3 = 114

      -3     -3   ← <em>subtract 3 from both sides of the equation</em>

3x = 111

÷3    ÷3   ← <em>divide both sides of the equation by 3</em>

<em> </em>X = 37

X ⇒ <em>first integer   = 37</em>

X + 1 ⇒ <em>second integer   = 38</em>

X + 2 ⇒ <em>third integer   = 39</em>

<em />

<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>

5 0
4 years ago
Read 2 more answers
A soccer team has played 25 games and has won 60% of the games and has played. WHat is the minimum number of additional games th
dybincka [34]

(15 games) is the minimum number of games the team must have played

4 0
3 years ago
Read 2 more answers
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