Answer:
If the equation is 3x^2+6y^2, when x=0 and y=2.
Then, 3(0)^2+6(2)^2=
So, 0+6(4)= 24
Therefore, the answer is 24.
Step-by-step explanation:
Answer:

Step-by-step explanation:
For #2, remember that
, so
Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=
. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number
, where a and b are any numbers, the conjugate is always
. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

Our answer is (28-3i)/(26)!
2.0076* 10^4
move the decimal 4 places to the right
20076.
20076 < 26970
Answer: 37, 38, and 39
Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.
3 consecutive integers can be represented as followed.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.
X + X + 1 + X + 2 = 114
We can simplify on the left side by combining the X's and the numbers.
3x + 3 = 114
-3 -3 ← <em>subtract 3 from both sides of the equation</em>
3x = 111
÷3 ÷3 ← <em>divide both sides of the equation by 3</em>
<em> </em>X = 37
X ⇒ <em>first integer = 37</em>
X + 1 ⇒ <em>second integer = 38</em>
X + 2 ⇒ <em>third integer = 39</em>
<em />
<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>
(15 games) is the minimum number of games the team must have played