Answer:
6/h = 10/40
Step-by-step explanation:
6/h = 10/40
F = 18 ft.
The law of cosines states
c² = a² + b² - 2ab cos C
Using our information, we have
c² = 23² + 16² - 2(23)(16)cos 52
c² = 529 + 256 - 736cos 52
c² = 785 - 736cos 52
c² = 331.8732
Taking the square root of both sides, we have
c = √331.8732 = 18.22 ≈ 18
9514 1404 393
Answer:
382 square units
Step-by-step explanation:
The central four rectangles down the middle of the net are 9 units wide, and alternate between 8 and 7 units high. Then the area of those four rectangles is ...
9(8+7+8+7) = 270 . . . square units
The rectangles making up the two left and right "wings" of the net are 8 units high and 7 units wide, so have a total area of ...
2×(8)(7) = 112 . . . square units
Then the area of the figure computed from the net is ...
270 +112 = 382 . . . square units
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<em>Additional comment</em>
You can reject the first two answer choices immediately, because they are odd. Each face will have an area that is the product of integers, so will be an integer. There are two faces of each size, so <em>the total area of this figure must be an even number</em>.
You may recognize that the dimensions are 8, 8+1, 8-1. Then the area is roughly that of a cube with dimensions of 8: 6×8² = 384. If you use these values (8, 8+1, 8-1) in the area formula, you find the area is actually 384-2 = 382. That area formula is A = 2(LW +H(L+W)).
Answer:
2nd one
Step-by-step explanation:
