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9966 [12]
2 years ago
13

I really need help can someone please help me I posted this before but no one answers pls help me quick don't be like other fool

s that spam pls
​

Mathematics
1 answer:
solmaris [256]2 years ago
8 0
P = 4ft

Explanation:
take 5 and 3, add them together = 8. "straight down to double its distance" so that would mean to do either 8 divided by 2 or 4 x 2. 4 x 2 - 3 = 5 (5 = final position). p = 4ft
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What is the perimeter of a square with side length: s cm
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s cm+s cm+s cm+s cm

Step-by-step explanation:

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3 years ago
Please Help With this question
Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

f(h(-2) =

h(-2)= 5(-2)= -10

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7 0
3 years ago
A leading bank is coming up with an investment that pays 8 percent interest compounded semiannually. What is the investment's ef
uranmaximum [27]
The effective rate is calculated in the following way:
r =  {(1 +  \frac{i}{n} )}^{n} - 1
where r is the effective annual rate, i the interest rate, and n the number of compounding periods per year (for example, 12 for monthly compounding).
our compounding period is 2 since the bank pays us semiannually(two times per year) and our interest rate is 8%
so lets plug in numbers:
r = {(1 +  \frac{8\%}{2}) }^{2}  - 1 \\ r =  {(1 +  \frac{1}{25}) }^{2}  - 1 \\ r =  \frac{676}{625}  - 1 \\ r = 0.0816 \: or \: 8.16\%
5 0
3 years ago
Twenty two quarts is equivalent to how many gallons?<br> 4.5<br> 5.5<br> C<br> 6.5<br> 7.5
marysya [2.9K]

Answer:

5.5 gallons

Step-by-step explanation:

There are 4 quarts in 1 gallon.

22 ÷ 4 = 5.5

I hope this helps :)

4 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
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