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vaieri [72.5K]
2 years ago
11

100-3x6+5-4= 63? help me its GEMDAS

Mathematics
1 answer:
Anon25 [30]2 years ago
4 0

Answer:

it's 86

Step-by-step explanation:

100-3x6+5-4

100-15+5-4

85+5-4

90-4

86

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Find the Error. Judith states that -|14| = 14 because the absolute value can never be negative. Find her mistake and correct it.
AURORKA [14]

Answer:

-14

Step-by-step explanation:

The negative sign is not inside of the absolute value sign so it would be -14

5 0
2 years ago
If the length of rectangle is x + 4 and the width is 3x - 5 what is the perimeter?
statuscvo [17]

Answer:

8x-2

Step-by-step explanation:

l = x+4

w = 3x-5

The perimeter is

P =2(l+w)

   = 2(x+4+3x-5)

Combine like terms

   = 2(4x-1)

Distribute

   = 8x-2

6 0
3 years ago
Read 2 more answers
Find the magnitude and direction in degrees of the vector v=6i+2 seq31​
masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the vector

v = 6i + 2√3j

The Magnitude of a vector:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

=\sqrt{6^2+\left(2\sqrt{3}\right)^2}

=\sqrt{36+12}

=\sqrt{48}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=\sqrt{3}\sqrt{2^4}

=4\sqrt{3}

The Direction of a vector:

tan Ф = y/x

y=2√3

x = 6

tan Ф = y/x

          = 2√3 / 6

           = √3 / 3                  

\theta \:=tan\:^{-1}\left(\frac{\sqrt{3}}{3}\right)

\:\theta \:=\frac{\pi \:}{6}=30^{\circ \:}

6 0
3 years ago
What is the equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3?
Alika [10]
<h3><u><em>Option B</em></u></h3><h3><u><em>The equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3</em></u></h3><h3><u><em /></u>y + 3 = \frac{2}{3}(x -5)<u><em /></u></h3>

<em><u>Solution:</u></em>

<em><u>The equation of line in point slope form is given as:</u></em>

y - y_1 = m(x-x_1)

Where, "m" is the slope of line

Given that,

slope = 2/3

m = \frac{2}{3}

The line passes through (5, -3)

Substitute m = 2/3 and (x_1, y_1) = (5, -3) in point slope form

y - (-3) = \frac{2}{3}(x -5)\\\\y + 3 = \frac{2}{3}(x -5)

Thus equation of line in point slope form is found

8 0
3 years ago
Please can anyone help me please​
Step2247 [10]
4.5, 4, 3.5, 3, 2.5, 2 and use the pencil and ruler, love a bit of MathsWatch
7 0
3 years ago
Read 2 more answers
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